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Extractions: Tuesday, June 8, 2004 Homework Help Forum Homework Help Experts Atmosphere You've probably already heard how humans are ruining the Earth's atmosphere, but what exactly is the atmosphere? The atmosphere is a layer of air the surrounds the Earth's surface. It includes mostly nitrogen, and other common gases such as oxygen, water vapor, and carbon dioxide. The atmosphere is divided into five sub-layers. They are the Troposphere, stratosphere, mesosphere, thermosphere, and exosphere. We will talk about them later on this page. The atmosphere also contains atmospheric pressure. Atmospheric pressure is the weight of the atmosphere itself. Air still has weight, even though it may seem very light. The atmosphere goes up to about 310 miles from the Earth's surface. Therefore, you can just imagine how much atmospheric pressure we receive. For example, the air weighs about fifteen pounds on every square inch of your body. If you don't like moisture, then be happy for atmospheric pressure. Atmospheric pressure decreases the amount of moisture in the air because it's lighter than air. Unfortunately, atmospheric pressure is also the reason why your ears pop when you go take off or land while on an airplane. Now let's talk about the five sub-layers of the atmosphere. First, at 12 miles at Earth's equator let's talk about the troposphere. It's only 5 miles thick at the north and south poles, but we live here so don't criticize its size! This is where all of the clouds, rain, and snow form as well.
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Extractions: homework help math, chem help? click Home Ask Questions Latest Answers ... Properties of Matter "FORMULATOR" SPEEDS UP HOMEWORK Formula: F = m x a FORCE: N MASS: kg ACCELERATION: m/s Physics Formula Calculator from http://tutor4physics.com Q. A120 lb person is being lifted aloft by a rocket which accelerates uniformly to an upward speed of 300 ft/sec in 2 sec. a) What is the upward acceleration in multiples of g? Mass of the man = 120lb Final speed of the rocket = 300 ft/sec Time = 2 sec Acceleration of the rocket can be calculated from first equation of motion v = u + at 300 = + a x 2 a = 150 ft/sec b) What is the apparent weight of the person during acceleration? Free body diagram: N - Normal reaction which is equal to the apparent weight of the man. mg - Actual weight of the man ma = N - mg N = ma + mg = m (a + g) = m (4.7g + g) = 5.7mg = 5.7 x 120 g = 684g = 684 lbf. Q. A short 10 gram string is used to pull a 50 gram toy across a frictionless horizontal surface. If a 3.0 x 10 Newton force is applied horizontally to the free end. Find the force of the string on the toy, at the other end. Mass of the string = 10 grams = 10 kg Mass of the toy = 50 gm = 5 x 10 kg Mass of toy + string = 10 + 5 x 10 = 6 x 10 kg Force applied F = 3.0 x 10 N
Extractions: e. none of the above choices are valid i r i As the earth moves closer to the sun, r decreases, but, mass of the system is constant. Q. A sphere shell has inner radius R, outer radius R, and mass M, distributed uniformly throughout the shell. Find the magnitude of the gravitational force exerted on the shell by a point particle of mass m located at a distance d from the center, outside the inner radius and inside the outer radius. Mass of the sphere = M Point P is at a distance of d from the center and there is a particle of mass m located there. The mass of the spherical shell that will cause force will be mass located between the spheres of radius d and radius R - R - R - R - R ) = [(d - R )M]/(R - R Thus force exerted on m is = G.m.M' / d
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